Find the relative extrema of f(x)=-x^3 - 1.5x^2 + 6x + 5 ; [-10, 10, -30, 10]?

Answer 1

The relative extrema (max and min) will be at locations -- values of x -- where the derivative f'(x) = -3x^2 -3x + 6 is equal to zero and the second derivative f"(x) = -6x -3 is not.

(If both f' and f" are equal to zero, it is an inflection point: a point where the slope is 0 but the curve resumes its original direction -- the point is neither a max nor a min, but it is a critical point)

Answer 2

hello

differentiate once & twice & equate to zero , then
get your peaks in the specified interval

Answer 3

i think it's 2