so it creates the right graph. Is it: ln (x) / -2?
2007-12-12 06:52:13 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Can't you just enter in -2*ln(x).
I get a graph, but I don't know if it is correct, it's been to long since I have done natural logs.
2007-12-12 07:01:13 · answer #1 · answered by RickSus R 5 · 0⤊ 0⤋
I dont get your question.
Why would you think that -2 ln x in math have to be entered as ln x / -2 in a calculator?
2007-12-12 07:01:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
On a TI-84, I think you would enter this in on the y= menu:
ln(x^(2))
Hope it's helpful!
2007-12-12 07:02:02 · answer #3 · answered by Runner 09 2 · 0⤊ 0⤋
It does like having the exponential: there could probable be an e^x button (or 2d functionality) as nicely as one for e which you would be able to easily use impressive. As for the 13, basically make the functionality y= 4e^(0.1t) - 13.
2016-10-01 10:52:03 · answer #4 · answered by thieme 4 · 0⤊ 0⤋
Whatever you do, do not under any circumstances consult your user's guide. Don't even try to experiment with it and see what happens. Just hope that someone who doesn't even know what kind of calculator you have will walk you through it.
2007-12-12 07:07:02 · answer #5 · answered by Dr D 7 · 0⤊ 0⤋
Try [ 2 ] [ +/- ] [ * ] [ x ] [ ln ]
2007-12-12 07:09:49 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋