Use the discriminate to determine the number of solutions for the equation 9x2 + 6x = -1.
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2007-12-12 06:23:39 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
9x2 + 6x + 1 = 0
b^2-4ac = 6^2-4*9*1 = 0
1 solution
2007-12-12 06:28:55 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
Write in elementary style so 9x^2 + 6x + a million = 0 a = 9, b = 6, c = a million b^2 - 4ac 36 - 4(9)(a million) = 0 If discriminant (D): D = 0 genuine, rational, equivalent D > 0 and appropriate sq.: genuine, Rational, Unequal D > 0 and not appropriate sq.: genuine, Irrational, Unequal D < 0 Imaginary So when you consider that D = 0, Roots are genuine, rational and equivalent
2016-11-26 01:26:22 · answer #2 · answered by fiddler 4 · 0⤊ 0⤋
9x2 + 6x = -1
9x2 + 6x+1=0
9x2 + 3x+3x+1=0
3x(3x+1)+1(3x+1)=0
(3x+1)(3x+1)=0
3x+1=0
3x=-1
x=-1/3
so there is 1 solution
2007-12-12 06:32:21 · answer #3 · answered by Siva 5 · 0⤊ 0⤋
b^2-4ac = 36 - 4x9x1 = 0
so it has two eq roots, so the answer is 1
2007-12-12 06:30:20 · answer #4 · answered by norman 7 · 0⤊ 0⤋