Two cities are1460 miles apart. A plane leaves one of them, traveling towards the other. At the same time a plane leaves the other city, traveling towards the first at an average speed of 380 miles per hour. How many hours will it take them to meet?
2007-12-12 06:08:21 · 4 answers · asked by higherlovetx 5 in Science & Mathematics ➔ Mathematics
I assume they are both traveling at 380 mph.
380t+380t = 1460
760t = 1460
t = 1..92 hours
2007-12-12 06:14:27 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
1460/380 = 3.84 time to travel for one aircraft to travel complete distance.
Assuming they travel at the same speed divid this answer by 2.
3.84/2 = 1.92hours
2007-12-12 14:15:44 · answer #2 · answered by pildriver69 3 · 0⤊ 0⤋
I'm missing one of the speeds I will assume is the same for both:
D1+D2=1460
V1=V2=380
T=T1=T2=D1/V=D2/V
(1460-D2)/380=D2/380
D2=1460/2 = 730
So T=1.92 hours
2007-12-12 14:14:28 · answer #3 · answered by artie 4 · 0⤊ 0⤋
760X = 1460
X = 1.92
1.92 * 380 = 730
730*2 = 1460
2007-12-12 14:12:54 · answer #4 · answered by APR 2 · 0⤊ 0⤋