Solve: sinx-1=0 for x.?

Answer 1

If your question is to solve
sin(x)-1 = 0 then you would first add 1 to both sides and get sin(x) = 1 and
sin(pi/2) = 1 because
arcsin(1) = pi/2
so x would be pi/2

Answer 2

sin x -1=0
sin x = 1

At this point, you can draw a sketch of a sine graph - the wave function starting at 0 going to one at 90 degrees, down to 0 at 180 degrees, -1 at 270 degrees back to 0 at 360 degrees.

Here is a diagram of one.

http://www.wsd1.org/waec/math/Pre-Calculus%20Advanced/Trigonometry/Graphing/images/sinxbasic.gif

as sin x = 1, u read from the graph where the graph is 1 -> at 90 degrees.

Alternatively u can use inverse sine function on your calculator for 1 to get 90. However this can cause difficulties if the graph is not a simple sine graph on its own, or if the domain is larger than 0

Answer 3

sinx-1=0
sinx=1
x=sin~(-1) ( meaning xequals sin inverse -1)
x=90 or pi/2

Answer 4

sin x = 1
x = pi/2 +/- 2npi, where n is any integer

Answer 5

sin(x)=1
For what x , sin(x)=1
x=arcsin(1)=pi/2