If the crytal was held at an angle of 18.0o to the beam. What was the wavelength of the X-ray radiation in nm ?
2007-12-12 02:28:27 · 3 answers · asked by chemical.garry 1 in Science & Mathematics ➔ Chemistry
.129
208*2*sin(18) = 128.55pm= .12855nm
2007-12-13 08:33:05 · answer #1 · answered by stars 2 · 0⤊ 0⤋
The equation you desire is Bragg's regulation of diffraction: n x lambda = 2 x d x sin(theta). Lambda is the wavelength, d is the gap between layers, and theta is the 18 stages. anticipate that n = a million (the conventional project - referred to as first-order diffraction). lambda = 2 x 216 pm x sin 18.0 = 324 pm, or 3.24 x 10^-10 m
2016-12-17 15:41:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
From simple geometry, wavelength = spacing x sin(angle).
The question is actually inside out. In reality, you know the wavelength and use the angle to find the spacing.
2007-12-12 08:22:23 · answer #3 · answered by Facts Matter 7 · 0⤊ 0⤋