2007-12-12 01:12:21 · 7 answers · asked by Cookie A 1 in Science & Mathematics ➔ Mathematics
ratio of sides is 16 :14 = 8 : 7
ratio of areas is 64 : 49
2007-12-12 02:45:59 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Let A represent the area of the larger rectangle, W stand for its width and L stand for its length.
Let a represent the area of the smaller rectangle, w stand for its width and l stand for its length.
Since the rectangles are similar, that means there is a constant ratio between the lengths of the sides.
16 / 14 = 8 / 7, so the ratio of the lengths is also 8 / 7.
That means we can say that L = (8 / 7) * l and W = (8 / 7)*w
We know that a = l * w.
Plugging in the values for L and W, we get:
A = (8/7) * l * (8/7) * w = 64/49 * l * w
So, the ratio of the areas is 64/49
2007-12-12 01:27:13 · answer #2 · answered by lhvinny 7 · 0⤊ 1⤋
Since the rectangles are similar, the ratio of the widths is equal to the ratio of the lengths
That is w1/w2 = L1/L2 = 16/14.= 8/7
Now, the ratio of the areas, A1/A2 = L1*w1 / L2*w2 = (L1/L2) * (w1/w2)
= (8/7) * (8/7)
= 64/49
2007-12-12 01:44:59 · answer #3 · answered by w4c~m3-5un 3 · 0⤊ 0⤋
call the length of the first rectangle x
the ratio of widths is 8:7
so the lenth of the second rectangle is 7x/8
the area of the first rectangle is 16x and the second is 12.25x
so the ratio is:
16:12.25
2007-12-12 01:23:40 · answer #4 · answered by mountainpenguin 4 · 0⤊ 2⤋
7:8
2007-12-12 01:26:53 · answer #5 · answered by detektibgapo 5 · 0⤊ 2⤋
(16/14)^2
2007-12-12 01:23:44 · answer #6 · answered by Anonymous · 0⤊ 1⤋
the ansew is 8:7 in ratio. i hope it is right! xxx
2007-12-12 01:38:04 · answer #7 · answered by rock_chick_1009 1 · 0⤊ 1⤋