why do balloons expand when it is exposed to hot air and why do balloons shrink when it is exposed to cold air
2007-12-11 22:59:21 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Charles' Law:
Temperature is directly proportional to Volume.
As the temperature increases, volume of a gas also increases.
As the temperature decreases, volume of a gas also decreases.
2007-12-12 00:41:45 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The short answer is that gases store energy (due to temperature) in their average velocity (where kinetic energy is energy due to speed and mass of a particle). If you throw a stone at a wall the wall must resist the impact of the stone. If you throw the stone harder the wall must exert even more resistance. The millions of particles of gas within a balloon are constantly striking the inner surface of the balloon resulting in a pressure that inflates (stretches) the balloon. If the gas is heated, the velocity of gas particles hitting the balloon increases, thus increasing pressure and further expanding the balloon. When exposed to cooler air, the gas within the balloon also cools and exerts less pressure and the (elastic) balloon overcomes the reduced pressure and shrinks.
2007-12-12 00:41:50 · answer #2 · answered by Kes 7 · 0⤊ 0⤋
The density of the air in the balloon is affected by the temperature~~
2007-12-11 23:07:31 · answer #3 · answered by burning brightly 7 · 0⤊ 0⤋
The easiest way to see this is to put a few scenarios into the ideal gas law: PV=nRT. Make sure you keep your units straight. As you can see from the equation, there is a relationship for pressure, volume, and temperature that you can play around with.
2007-12-11 23:20:09 · answer #4 · answered by TheSkeptic 2 · 0⤊ 0⤋