absolute value of 2x+3
minus 4 = 7
2007-12-11 17:21:56 · 6 answers · asked by Change 2 in Science & Mathematics ➔ Mathematics
[2x+3]-4=7
[2x+3]= 11
2x+3=11 & -(2x+3)=11
x = 4 x= -7
2007-12-11 17:27:18 · answer #1 · answered by Anonymous · 1⤊ 1⤋
I2x+3I=11
2x+3=11
2x=8
x=4
2x+3=-11
2x=-14
x=-7
2007-12-11 17:27:03 · answer #2 · answered by Armine 3 · 0⤊ 1⤋
|2x + 3| - 4 = 7 // add 4
|2x + 3| = 11
Check two regions:
1. Where 2x + 3 >= 0
2x >= -3
x >= -1.5
---------------------------
|2x + 3| = 11
2x + 3 = 11
2x = 8
x = 4
2. Where 2x + 3 < 0
2x < - 3
x < - 1.5
|2x + 3| = 11
-(2x + 3) = 11
2x + 3 = -11
2x = - 14
x = -7
=========================
x=4 or x=-7
2007-12-11 17:28:42 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
x=+ or - 4
2007-12-11 17:27:39 · answer #4 · answered by michaelstjohn2001 5 · 0⤊ 1⤋
(2x+3)=10
2x+3=10 or 2x+3=-10
x=7/2 or-13/2
2007-12-11 17:25:58 · answer #5 · answered by someone else 7 · 0⤊ 1⤋
2x + 3 - 4 = 7
2x = 8
x = 4
Answer: x = 4
Proof:
2(4) + 3 - 4 = 7
8 - 1 = 7
2007-12-11 17:28:59 · answer #6 · answered by Jun Agruda 7 · 3⤊ 1⤋