can someone help me on these problems
1.write 2^8*16^3*64 as a power of 4
2007-12-11 16:06:51 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
2^8 = 4^4
16^3 = 4^6
64 = 4^3
4^4 * 4^6 * 4^3 = 4^13
2007-12-11 16:14:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2^8 is the same as (2^2)^4 and 2^2 = 4 so that part = 4^4
16^3 is the same as (4^2)^3 because 4^2 = 16 so that = 4^2*3 or 4^6
64 is the same as 8*8 or 4*2*4*2 and 2*2 = 4 so you have 4*4*(2*2) or 4*4*4 or 4^3
so you have (4^4)*(4^6)*(4^3) and you add the exponents to get 4^(4+6+3) = 4^13
2007-12-12 00:22:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2^8 * 16^3 *64=4^4*4^6*4^3= 4^13=1,073,741,824
2^8=256=4*4*4*4=4^4
16^3=4096=4*4*4*4*4*4=4^6
64=4*4*4=4^3
2007-12-12 01:42:40 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
you're gonna need to toss in some parentheses in there first
2007-12-12 00:12:33 · answer #4 · answered by djackal1 2 · 0⤊ 1⤋