I'm familiar with the General Rule: U^n du , but I don't think it will work in this case.
please help!
2007-12-11 15:09:03 · 7 answers · asked by Conservative Jesus 1 in Science & Mathematics ➔ Mathematics
I = ∫ x^5 + 4 x ³ + 3 x dx
I = x^6 / 6 + x^4 + 3 x ² / 2 + C
2007-12-14 02:15:19 · answer #1 · answered by Como 7 · 2⤊ 1⤋
maybe distribute it through?
x^5 + x^3 +3x^3 + 3x
=x^5 +4 x^3 + 3x
now just do a backwards power rule for all 3 terms
2007-12-11 15:12:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(x^3+3x)(x^2+1).dx
(X^5+X^3+3X^3+3X).dx
(X^5+4X^3+3X).dx hence
the result of intregation =1/6X^6+X^4+3/2 X^2
2007-12-11 15:18:25 · answer #3 · answered by Faisal R 3 · 0⤊ 0⤋
multiply them first...
â« x^3*x^2 + 3x*x^2 + x^3 + 3x dx
= â« [x^5 + 4x^3 + 3x] dx
then you can use the power rule....
finish....
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2007-12-11 15:12:52 · answer #4 · answered by Alam Ko Iyan 7 · 0⤊ 1⤋
Just mulitply out the expressions, then integrate term by term. This one is easy.
2007-12-11 15:11:46 · answer #5 · answered by Anonymous · 1⤊ 0⤋
Product rule and exponent rule.
2007-12-11 15:11:30 · answer #6 · answered by Gregor Samsa 2 · 0⤊ 0⤋
expand the equation first. then integrate each term and add them together! you know how right?? email me if you still need help!
2007-12-11 15:11:58 · answer #7 · answered by XOXO 5 · 0⤊ 0⤋