i dont get how to solve this algebra 2 question?!?!?! the x2 in the problem is x squared in case that was confusing =)...
but yea i just really dont know how to set it up!
2007-12-11 15:03:57 · 9 answers · asked by angeltearz27 2 in Science & Mathematics ➔ Mathematics
plug 4x into all the x's
(4x)^2 +7
2007-12-11 15:07:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I just had this test in my algebra 2 class as well. This is called the composition of two functions. What this says is g(x) is a function of f(x). Simply plug g(x) into the x variable for f(x).
f(x)=(4x)^2+7
f(x)16x^2+7
2007-12-11 15:07:58 · answer #2 · answered by angrytwinkie@sbcglobal.net 2 · 0⤊ 0⤋
basically, you plug 4x into the equation:
x2 + 7 as x.
So you would have:
(4x)^2 + 7
and that equals:
16x^2 +7
(just the x is squared)
2007-12-11 15:08:19 · answer #3 · answered by BlackDan 2 · 0⤊ 0⤋
4x + 7(-3x - 5) = -49 - 3x 4x - 21x -35= -49 -3x times the 7 out -17x - 35= -49 -3x combined like terms -14x = -14 moved -3x over to other side as well as -35 x=1 divide 14 x=1
2016-05-23 04:04:54 · answer #4 · answered by janell 3 · 0⤊ 0⤋
It is (4x)^2 + 7
In f(g(x)), g(x) is nothing more than a variable to f(x). You know, g(x) is 4x. Then, give f(x) this variable.... In another words, substitute 4x as x to the f(x).
Then you get (4x)^2 + 7
Be very careful about the notation... it is NOT 4x^2. It is (4x)^2. Additionally, you can simplify this to 16x^2
2007-12-11 15:09:12 · answer #5 · answered by tkquestion 7 · 0⤊ 0⤋
Okay, so... since you have a g(x) inside of a f(x)..
Here's an example, maybe you can try to figure yours out with my example.
F(g(x)); f(x) = x + 1, g(x) = 2^2
So... since g(x) is inside f(x) then you substitute g(x) for every x in the f(x) problem.
Therefore you will get...
f(g(x)) = (2^2) + 1
See how I put (2^2) where the x is in the f(x) function?
After you plug it in, you just solve.
So your answer would be..
f(g(x)) = (2^2) + 1
f(g(x)) = (4) + 1
f(g(x)) = 5
Good luck!
2007-12-11 15:10:09 · answer #6 · answered by lovely x lucie 2 · 0⤊ 0⤋
hm,Did you remember to do BEDMAS?
B = Brackets (x + y)
E = Exponets 6*
D = Division 2/3
M = Multiplcation 6 x 111111
A = Addition 56+ 6
S = Subtraction 7 - 3
2007-12-11 15:08:47 · answer #7 · answered by Mike007 2 · 0⤊ 0⤋
f(g(x)) is going to equal (4x)^2 + 7
When you see something like f(g(x)), you put the other equation into the original. So in this case, you put g(x) where x is in f(x).
2007-12-11 15:08:40 · answer #8 · answered by Caress R 1 · 0⤊ 0⤋
f(x)=x^2, now put g(x) into the x....
f(g(x))= (4x)^2+7=16X^2+7
YAY!
2007-12-11 15:08:30 · answer #9 · answered by kibitzor 2 · 0⤊ 0⤋