Balanced Equation for...?

Question

Solid copper is added to nitric acid, and copper(II) nitrate, nitrogen dioxide, and water are produced.

What's the balanced equation for this?

The skeleton equation would be like;;

Cu + HNO3 yields to CU(NO3)3 + NO2 +H2O

The numbers are subscript, of course.

Answer 1

Cu + 4 HNO3 ---> Cu(NO3)2 + 2 NO2 + 2 H2O

Answer 2

This reaction actually produces NO, which immediately reacts with O2 in the air to give NO2

3 Cu + 8 HNO3 ---> 3 Cu(NO3)2 + 2 NO + 4 H2O

I did not balance it by sight, I did so using half-reactions. These are the unbalanced half-reactions, written in net ionic form.

Cu ---> Cu2+

NO3- ---> NO

These are the balanced half-reactions

Cu ---> Cu + 2e-

3e- + 4H+ + NO3- ---> NO + 2H2O

In net ionic form, the reaction is:

3 Cu + 8 H+ + 2NO3- ---> 3 Cu2+ + 2 NO + 4 H2O

Answer 3

copper II nitrate is Cu(NO3)2

Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

Answer 4

At a possibility: TiO2 + 2C + 2Cl2 --> TiCl4 + 2CO C is a sturdy, Cl2 a gas (i think of) and CO is definately a gas. No clue approximately the different 2. Why no longer seem it up? you've gotten documents tables or some thing.