A. minimum
B. Maximum
2007-12-11 13:41:38 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y = ax^2 + bx + x , a not equal to 0 is an equation of a parabola.
Now, if a > 0 the parabola open upwards (like U) therefore it has minimum value.
Hope that was helpful
2007-12-11 13:47:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
What level of math are you taking?
By graphing, you can tell, it has the minimum, but there are no maximum. It goes to positive infinity.
By recognizing x being raised to the second power and co-effecient being positive (ONE), you know the graph opens UP. That means there is minimum, but no maximum.
To do this mathmatically, you will have to involve calculus, and work with derivatives like this:
y=x^2-6x+7
y'=2x-6 ... find the first derivative of the function
Find the point where slope becomes zero
0=2x-6; x=3
Since there is only one point where y' is zero, there is only one point where curve changes directions
y''=2 ... second derivative
Since second derivative is positive, it is concave UP
That means
graph comes from positive infinity down wards and when x=3, it changes direction and goes up to the infinity.
You can take any of the above answers depending on your grade. Basic algebra to calculus....
2007-12-11 13:51:36 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
It is a quadratic equation with a positive 'a' value in ax^2 + bx + c, so the parabola will open upward. The answer is A and the minimum value calculates to be -2. The coordinate is (3,-2).
2007-12-11 13:47:03 · answer #3 · answered by SarahJ123 2 · 0⤊ 0⤋
y = x² - 6x + 7 = (x - 3)² - 2 So the minimum value is -2 when x = 3.
2016-05-23 03:49:44 · answer #4 · answered by kecia 3 · 0⤊ 0⤋
X^2 is always positive so it is going to dominate and there will not be a maximum; but for small values of X, -6X will dominate and the value of Y will be negative, so there is a minimum. You have to set the differential of the equation to zero to find the minimum.
2007-12-11 13:58:47 · answer #5 · answered by Russell K 4 · 0⤊ 0⤋
It has a minimum, no maximums for it is a parabolic function that opens upward.
For minimum, (I'm just gonna use calculus here) it is when the derivative of the function is zero. The derivative of the function is 2x - 6. x = 3 when the derivative is zero. So the answer is, after you plug in 3 for x into the original equation:
(3 , -2)
Really, you just need to graph this to find the answer...
2007-12-11 13:49:03 · answer #6 · answered by Acorns 3 · 0⤊ 0⤋
any parabola with a positive number before x^2 faces up like a smile so the equation has a minimum value: A.
2007-12-11 13:46:04 · answer #7 · answered by Nati F 3 · 0⤊ 0⤋
It has a minimum.Because a > 0, the graph opens upwards (like a U) making it have a minimum.
Hope this helps.
2007-12-11 13:46:30 · answer #8 · answered by 24inogedfdknflerg 3 · 0⤊ 0⤋
y = x² - 6x + 7
y' = 2x - 6 = 0 at (3,-2)
y" = 2 > 0 so y has a minimum at (3,-2).
2007-12-11 13:46:23 · answer #9 · answered by DWRead 7 · 0⤊ 0⤋
B. Minimum, because the parabola opens upwards
2007-12-11 13:46:51 · answer #10 · answered by rlk_117 3 · 0⤊ 0⤋