Ok, I did that part...but how in the world am i supposed to graph the -2y=-x -(-3) ?!?

Question

...I changed the x-2y=-3 to -2y=-x-3, then to y=x/2-3...but how do i put y=x/2-3 on a graph?

Answer 1

-2y=-x-[-3] Take the 3 out of the parenthesis. Now we have -2y=-x+3. Now set x equal to zero and solve for y. When x=0 then y=-3/2. Locate and mark that point on the y axis of your graph and call it point A. Now set y equal to zero and solve for x. When y=0 then x=3. Locate and mark that point on the x axis of your graph and call it point B. Now draw a straight line from point A to point B on your graph. Now extend this straight line to infinity in both directions and you will have a graph of the original equation.

Answer 2

Firstly, the equation is actually y = x/2 +3/2
... x-2y=-3
... x +3 = 2y
... (x+3)/2 = y
... y = x/2 +3/2

(you forgot to divide the 3 by two, when you halved the left hand side of the equation), and the ± signs got confused.

To graph this find out two points on the graph;
when x = 1:
y = x/2 +3/2
y = 1/2 + 3/2 = 4/2 = 2
... the point is (1, 2) ... plot the point on the graph

when x = 3; (you can choose any value here)
y = x/2 +3/2
y = 3/2 +3/2 = 6/2 = 3
... the point is (3, 3) ... plot the point on the graph

You now have two points on the graph, if you connect them with a ruler (and continue the line on either end) you will have graphed the equation!

Note you can do this with only two points because their is no "to the power of" in the equation, if you had y= SomethingXSQUARED, or CUBED etc (IE y = 3x² +12) then you would need more points, but for a linear equation two points are enough to be able to draw the whole graph

Answer 3

if you're graphing it, u have 2 use simples values of x. Consider x=0, x=1, x=2, x=3, x=4, x=5, x=-1, x=-2, x=-3, x=-5, and find the value of y for each value of x. then you will have points with [x,y] coordinates that you will place on the graph. for example, if for x=1 you find the value of y to be -2, then your point will be located at the intersection of 1 on the x axis and -2 on the y axis. you can use a ruler to draw a line parallel to the x axis that will go through 1 and another line parallel to the y axis. Where they cross is your point. Then you have to erase the lines back. Do the same for all the values of x that I noted above (-5 to 5) and you will have your graph.
trust me it can be fun once u learn how 2 do it.

Answer 4

Ok, the equation is this:

solving:
x-2y=-3
-2y=-x-3

Divide not only the -2 and -x by -2, but also the -3.
SO:
y=1/2x+3/2

To graph, 3/2 is 1 and 1/2. Start at that point on the y-axis, then go up one point and then right 2 points. Repeat the up and over process and you will have your line.

Answer 5

Pick 5 values for "x" and the calculate what y would be. For example, if x=0, y = -3.

Once you have about 5 coordinates (0,-3) then put them on a graph and draw a line between them.

Use x=-2, -1, 0, 1, 2 and figure out y for each.

Answer 6

1. -2y=x-(-3)
^simplify
2. -2y=x+3
^move -2 to the other side to get y by itself
3. y= -1/2x +-3/2
^ 3/2 is the y intercept...so put it on the y axis on your graph
-1/2 is the slope. so from -3/2, move down 1, left 2, down 1, left 2, down 1, left two, until you have your line
=]]

Answer 7

5x-2y:-1 5x+1:2y divide by 2 5/2x+1/2:y 1/2 is the y intercept 5/2 rise/run (up 5 down 2) slope x-3y:5 1/3x-5/3:y -5/3 y int 1/3 rise/run (up1 down 3) slope for x int let y:0 and solve for x

Answer 8

it would end up being y= 1/2x-3 which the (1/2) is the slope which you go the -3 and from there go up 1 right 2 and repeat that and that will make the line

Answer 9

omg we are learning this in my class. but we just started. i dont kno that much . good luck =D