math help?

Question

a private airplane leaves an airport and flies due south at 192km/h. two hours later a jet leaves the same airport and flies due south at 960km/h.

when will the jet overtake the plane?

Answer 1

here is your equation:
384 + 192T = 960T
384 is the distance traveled by the private plane in the 2 hours
T is the time multiplier used for both the private (182T) and the 960T)
the equal sign (=) represent the point when the distance covered by the jet will be the same as the distance covered by the private plane .. now you just have to solve for T

Solving for T in terms of HOURS
384 + 192T = 960T
384 = 960T -192T
384 = 768T
768T = 384
T = 386 ÷ 768
T = 1/2
1/2 hour = 30 minutes

ANS: 30 minutes

Answer 2

Let T represent the time the planes pass.
192T is the distance the private plane travels.
960(T-2) is the distance covered by the jet.
So: 192T = 960T - 1920
Or: 960T - 192T = 1920
768T = 1920
T = 2.5 hours after private plane leaves.