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I believe this requires the pigeon hole principle and would like a solution and explanation.

2007-12-11 09:44:18 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

The pigeonhole principle states that, given two natural numbers n and m with n > m, if n items are put into m pigeonholes, then at least one pigeonhole must contain more than one item.

Imagine 26 boxes each labeled with a letter A through Z. If you take each student's name, you can put them in one of the boxes based on the first letter of their last name. But since you have 30 names and 26 boxes, at least one box will have more than one name in it. This is equivalent to saying that at least two students will have names that begin with the same letter.

2007-12-11 09:54:56 · answer #1 · answered by Puzzling 7 · 0 0

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