I assume you are talking about drawing on an infinite plane and that these are infinite lines.
As long as none of them are parallel (or the same line) *and* as long as they don't all 3 intersect at a common point. If they do intersect at a common point (see picture), they *would not* form a triangle. Same thing with parallel lines.
2007-12-11 09:36:23
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answer #1
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answered by Puzzling 7
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Yes, if you were to draw them on a piece of paper, they'd be in the same plane. If they're not in the same plane, you might never get a triangle. Also, none of the lines can be parallel; they must intersect. Keep in mind, a line keeps going -- that's why we put arrows on the ends of it.
that's it! :)
2007-12-11 09:37:37
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answer #2
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answered by Marley K 7
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take the three line segments and label them as a, b, and c... now plug them into the equation: perspective C = cos^-a million*(a^2 + b^2 - c^2)/(2*a*b) this provides you with an perspective do the comparable element for all the factors perspective B = cos^-a million*(a^2 + c^2 - b^2)/(2*a*c) perspective A = cos^-a million*(b^2 + c^2 - a^2)/(2*b*c) if all the angles upload as much as one hundred eighty ranges, then the segments make a triangle...in the event that they do no longer, or your solutions to any of those equations does not paintings, then that isn't any longer a triangle
2016-10-11 02:11:28
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answer #3
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answered by ? 4
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Three coplanar lines always form a triangle unless they are parallel (any two or all three) or concurrent (all three meeting at the same point).
2007-12-11 09:40:26
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answer #4
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answered by sv 7
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Yes, unless two or more of them were parallel to each other. AND this also assumes the lines are restricted to a Euclidian plane.
2007-12-11 09:39:36
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answer #5
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answered by MP314159 1
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Yes, unless two or more of them were parallel to each other.
2007-12-11 09:34:36
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answer #6
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answered by shaan 4
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