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I've just spent hours and hours doing maths (in case you couldn't tell by the question). Logic would say that when you have a graph with two lines and you calculate the x and y axis cross points and draw the graph that the point where the two meet would be accurate on the graph after you solved the in-equation of the two lines i.e I drew a graph very carefully, drew in the lines, made sure the scale was ok, but then when I calculated the meeting point it wasn't anything like on my graph. I've spent almost two hours with my boyfriend trying to figure out where I went wrong, he can't find it.. I can't find it.. how come things that work sometimes don't work on others? It's supposed to be math after all ;)

2007-12-11 08:13:50 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

I know my terms aren't correct, that's cos I'm studying math in a foreign language and don't know the English terms :S

2007-12-11 08:14:41 · update #1

1.6x + y < or equal to 120
20x + 50y < or equal to 3000

The point is to find maximum profit.

I got the x and y axis cutting coordinates...
first graph: (0,120)(75,0)
second: (0,60)(150,0)

On my graph I get the meeting point as around (50,40) but after solving the equations (90,24).
Any help would be greatly appreciated :)

2007-12-11 08:30:17 · update #2

Dunno if you need this but...

The maximum profit line goes like 30x + 40y = "biggest profit I can get" and it should cut through the meeting point at -3/4 but the meeting point is supposed to be where the greatest profit is if you get my meaning.. I have a math test tomorrow and this'll come up.. I just know it will lol

2007-12-11 08:33:12 · update #3

Okey dokey.

1. y=120-1.6x
2. y=60-0.4x

The in-equation:
1.6x + y = 120 | *(-50)
20x + 50y = 3000

-80x - 50y = -6000
20x + 50y = 3000

-80x = -6000 | *(-1)
20x = 3000

100x = 9000
x = 9000/100 = 90

20*90 + 50y = 3000
1800 + 50y = 3000
50y = 1200
y = 24

2007-12-11 08:41:26 · update #4

That's fantastic, thank you so much! So basically I shouldn't mess around with the negative numbers so much at just leave them be for a while. You've just aided me in having a good nights sleep, much thanks :)

2007-12-11 09:13:38 · update #5

2 answers

I get the same intersection point on the graphs... so maybe we need to look at how you solved the two equations.

1.6x + y = 120 | *(-50)
20x + 50y = 3000

-80x - 50y = -6000 | * (-1)
20x + 50y = 3000

80x + 50y = 6000
20x + 50y = 3000

*Subtracting* the equations at this step:
60x = 3000
x = 3000 / 60
x = 50

20*50 + 50y = 3000
1000 + 50y = 3000
50y = 2000
y = 40

-------------------
The graph of the 3 lines are given below:
Pink: 1.6x + y ≤ 120
Green: 20x + 50y ≤ 3000

Red: 30x + 40y ≤ 3100

2007-12-11 08:33:30 · answer #1 · answered by Puzzling 7 · 1 0

Give us the two equations and maybe we can work out where you're going wrong.

2007-12-11 08:20:46 · answer #2 · answered by Anonymous · 0 1

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