2007-12-11 07:57:49 · 5 answers · asked by Cookie A 1 in Science & Mathematics ➔ Mathematics
Area of a square is half the product of the diagonals. Since the diagonals are equal in a square, the product of diagonals is 64cm and half of 64 is 32 square centimeters.
area of a square with a diagonal of 8cm= 32 cm sq
2007-12-11 08:01:07 · answer #1 · answered by Anonymous · 3⤊ 0⤋
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RE:
Find the area of a square with a diagonal of 8cm.?
2015-08-18 05:47:43 · answer #2 · answered by Tiffany 1 · 0⤊ 0⤋
Area Of A Square
2016-09-25 19:57:28 · answer #3 · answered by lashbrook 4 · 0⤊ 0⤋
area of square = 1/2 diagonal^2 = 1/2 (8cm)^2 = 32 cm^2
2007-12-11 08:02:36 · answer #4 · answered by sv 7 · 1⤊ 0⤋
Area of Square = s^2
Solving for s:
s^2 + s^2 = 8^2
2s^2 = 8^2
s = sqrt[8^2/2]
s = sqrt(32)
Therefore,
A = [sqrt(32)]^2
A = 32 ANS
teddy boy
2007-12-11 08:11:00 · answer #5 · answered by teddy boy 6 · 1⤊ 1⤋
Pythagoras says 8^2 /2 is one side squared, that's 32.
Area of the square is also one side squared.
2007-12-11 08:03:00 · answer #6 · answered by Robert S 7 · 0⤊ 0⤋
pythagorean: 8^2=x^2+y^2
in this case, since it is a square, x=y
so: 8^2=x^2+x^2=2x^2
solve for x
64/2=x^2
x=sqrt(32)
area of a rectangle (or square) = length*width
in this case, length and width are both x
so x*x=x^2
sqrt(32)^2=32
2007-12-11 08:02:36 · answer #7 · answered by Matt G 2 · 0⤊ 0⤋
Jeez, I hope that people think this through before answering these math problems. Cookie might get this question wrong for homework or something...
Listen to Teddy Boy and Matt G. Their calculations are correct.
2007-12-11 08:19:06 · answer #8 · answered by Michael K 3 · 1⤊ 0⤋