Find the resulting force on the wire..?

Question

a flat wire 20cm long is placed in a magnetic field with strenght 0.10T and perpendicular to it.. A current of 1 ampere is induced in the wire. Find the resulting force on the wire if the force is given by F[arrow above]= LI[arrow above on i] X B[arrow above].
L is the lenght of wire, I is current and, B is the magnetic field.

Plz. show/explain every steps.

Answer 1

F = L i × B, given.

So the magnitude of F is given by

|F| = L |i| |B| |sin(θ)|

where θ is the angle between the vectors i and B. Since the wire (and hence also the current) is perpendicular to the magnetic field, |sin(θ)| = 1. Therefore,

|F| = (0.20 m)(1 amp)(0.10 T) = 0.02 newtons

and the direction of F is perpendicular to both the current vector and the magnetic field vector, as given by the right hand rule.

Note: I converted the wire length from cm to meters because T (tesla) is an SI unit. The units on T are kg/(amp-sec²)

Answer 2

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