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A magnetuic field (B[with arrow above]) exerts a force on an electric charge (q )moving at a given velocity (v[with arrow above]). The force is the cross product given by F[with arrow above] = qv[arrow above{on v only}] x B[arrow above]. Find a force acting on a proton (q= 1.6 x 10^-19 C) moving at 3/4 speed of light (3.0 x 10^8 m/s) perpendicular to the field.

please show every step of the problem

2007-12-11 07:15:29 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

Better move this to the physics section.

2007-12-11 09:55:29 · answer #1 · answered by Curt Monash 7 · 0 0

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