formula
n(n+1) =25*26=650
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as the sum of the 1st 25 numbers
1,2,3,4,5......,25
=25*26/2
the even number = this sum *2 =25*26
2007-12-11 06:40:17
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answer #1
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answered by mbdwy 5
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0 + 2 + 4 + 6 + 8 + 10 + 12 + 14 +16 +8 +20 + 22 + 24 + 26 + 28 + 30 + 32 +34 +36 + 38 + 40 +42 + 44 + 46+ 48
= 668
2007-12-12 07:51:12
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answer #2
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answered by Rayan Ghazi Ahmed 4
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2 + 4 + 6 + 8 + 10 = 30
12 + 14 + 16 + 18 + 20 = 80
22 + 24 + 26 + 28 + 30 = 130
just 1 to 25 even is 156
32 + 34 + 36 + 38 + 40 = 180
42 + 44 + 46 + 48 + 50 = 230
650
do you see the pattern that develops?
2007-12-11 06:33:22
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answer #3
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answered by Jim L 3
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Sum Of First 50 Even Numbers
2016-11-10 08:54:15
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answer #4
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answered by Anonymous
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2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50=650 That is the corroect answer.
2007-12-11 06:33:05
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answer #5
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answered by Anonymous
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The first 25 even numbers are the even numbers starting at 2 and ending at 50. One easy way to add up lists of numbers like this is like follows:
50
48+2 = 50
46+4
44+6
42+8
40+10
38+12
36+14
34+16
32+18
30+20
28+22
26+24
As you can see, there are 13 sets of even numbers totaling 50 each. So, just multiply.
50*13 = 650
This works for adding any series of numbers. For example, the sum of the numbers between 1 and 100 is (100+1) * 50 or 5050.
2007-12-11 06:44:17
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answer #6
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answered by John73 5
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2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50= 650
2007-12-11 06:30:53
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answer #7
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answered by dulaney78 1
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2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50= 650
2007-12-11 06:30:32
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answer #8
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answered by donkeypunch'em 3
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The first even number is 2.
The 25th even number is 50.
The 13th even number is 26.
There are 12 numbers before and after the 13th no.
Therefore: (50+2) x 12 + 26 = 624 + 26 = 650.
2007-12-11 06:41:01
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answer #9
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answered by rkeech 5
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2 + 4 + 6 + ... + 50
=2 ( 1 + 2 + 3 + ... + 25 )
=2 ( 25 ) ( 25 + 1 ) / 2
=( 25 ) ( 25 + 1 )
=650
2007-12-11 06:30:58
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answer #10
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answered by jgoulden 7
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