A 4.2g packet of kool-aid was combined with 10 g of sugar and combined with 0.5L .What is the %compositon of?

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A 4.2g packet of kool-aid was combined with 10 g of sugar and combined with 0.5L .What is the %compositon of?

2007-12-11 06:03:17 · 2 answers · asked by kat 1 in Science & Mathematics ➔ Chemistry

2 answers

.5L= m= v*d= 500ml*1g/ml=500g

4.2g kool-aid +10g sugar+ 500g =

514.2g total weight

example,

kool-aid%= 4.2g/514.2g=.0082

.0082*100%= .82%

kool-aid=.82%

sugar =1.94%

.5L=97.24%

2007-12-11 07:00:49 · answer #1 · answered by bige1236 4 · 0⤊ 0⤋

mass/volume %= (4.2g +10g)/500ml x 100=3% (m/v) kool-aid plus sugar.

2007-12-11 06:31:25 · answer #2 · answered by jacob s 7 · 0⤊ 0⤋