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evaluate the integral of

sec^2xtanxdx, u=tanx

can someone explain how to do this?

I'd appreciate any help.

Thanks.

2007-12-11 05:44:35 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

You know u=tanx.

Take the derivative:

du = sec^2x dx

Now substitute into the original equation.

The tanx becomes u, and the sec^2x dx becomes du:

u du

Integrate:

(1/2)u^2 + C

Substitute back in u=tanx:

(1/2)tan^2x + C

2007-12-11 05:53:46 · answer #1 · answered by ed315 2 · 1 0

let u = tanx du=sec^2xdx

so the integrals tanx sec^2xdx becomes udu
= u^2/2 + c
= 1/2 tan^2x + c

2007-12-11 13:54:04 · answer #2 · answered by norman 7 · 1 0

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