calculate the angular momentum of Earth that arises from its spinning motion on its axs Ie=0.3331MeRe^2.?

Question

answer in units of kgm^2/s

Answer 1

The moment of inertia of a sphere about an axis passing through the center i s

2/5 m r²

where m and r are the mass and radius of the sphere - in your case, the Earth.

The angular momentum is then

L = I ω

where

ω = angular velocity of the Earth
ω = ( 2π ) / ( 1 day ) ( 24 hours / day ) ( 3600 sec / hour )

Answer 2

angular momentum, L 2nd of inertia, I angular velocity = w L = I w now contained in terms of a around merchandise the 2nd of inertia on the subject of the line passing via the centre of mass is I = (2/5) * M * R^2 the place M = 5.ninety 8 * 10^24 kg, is the mass of the physique and R = 6.32 * 10^6 m is the radius of the physique. we are able to paintings out the angular velocity of the earth considering that all of us comprehend the earth take 24 hours to end an entire 2 pi radian rotation so w = 2 * pi / (24 * 60 * 60 ) radian according to 2nd So from the 1st equation L =(( 2/5) * 5.ninety 8 * 10^24* (6.32 * 10^6 )^2 * 2 * pi / (24 * 60 * 60 ) )kg meter sq. according to 2nd