find an equation perpendicular to line 4x+3y=-7 ; containing point(-7,-7)?

Answer 1

y = -4/3x -7

slope of perpendicular line = 3/4

(y+7)/(x+7)=3/4
4(y+7)=3(x+7)
4y - 3x = -7

Answer 2

Get the original equation into the form y=mx+c, so you can find the gradient

4x+3y=-7
3y=-7-4x

y= -4/3x - 7

now you know the gradient of the above line is -4/3

-1 divided by any gradient is the perpendicular gradient, so -1 / -4/3 = 3/4

Answer's gradient is 3/4

Easiest equation to use is(y-y1)=m(x-x1)

Because all you have to do is put the contact point co-ordinates in for x1 and y1

So the answer is (y+7)=3/4(x+7)

Remember y-y1 = y- -7= y+7, the signs have changed