Question on Simple Machines?

Question

A weight of 600.0 N is raised 4.65 m by a pulley system which has an IMA of 3.00.
How far must the effort travel to accomplish this?
What effort is required to maintain dynamic equilibrium if friction is neglected?

Effort Distance = ________________ m

Effort Force = ________________ N

Answer 1

Effort Distance = increased
Effort Distance=distance raised x IMA
Effort Distance= 4.65 x 3.00= 13.95

Effort Force = decreased
Effort Force = Weight / IMA = 600/3.00= 200