2007-12-11 05:00:25 · 7 answers · asked by Jenny D 1 in Science & Mathematics ➔ Mathematics
(2 x 121)(x^6) (y^4)
11√2 x ³ y ²
2007-12-11 05:29:53 · answer #1 · answered by Como 7 · 4⤊ 0⤋
OK
sqrt(242x^6y^4) =
sqrt((2)(121)x^6y^4)=
11 x^3 y^2 sqrt2
(notes: sqrt 121 = 11; sqrt x^6 = x^3, sqrt y^4 = y^2)
Hope that helps.
2007-12-11 13:05:50 · answer #2 · answered by pyz01 7 · 0⤊ 0⤋
11 sqrt(2) x^3 y^2
2007-12-11 13:03:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
we need to split up the expression into 3 parts
sqrt(242) x sqrt(x^6) x sqrt(y^4)
we can split up sqrt(242) into sqrt(121) x sqrt (2)
so sqrt(121) x sqrt (2)x sqrt(x^6) x sqrt(y^4)
=.....11...........xsqrt(2) x......x^3............y^2
11x^3y^2 sqrt(2)
2007-12-11 13:08:02 · answer #4 · answered by Ari 6 · 0⤊ 0⤋
sqrt(242x^6y^4) = sqrt(2)sqrt(121)sqrt(x^6)sqrt(y^4)
= 11x^3y^2sqrt(2)
2007-12-11 13:05:45 · answer #5 · answered by kindricko 7 · 0⤊ 0⤋
sq.rt. of 242x^6y^4
sq.rt.(242x^6y^4)
sq.rt.(2*121*x^2*x^2*x^2y^2*y^2)
sq.rt.(2*{11}^2*{x}^2{x}^2{x}^2*{y}^2*{y}^2)
11*x*x*x*y*y*sqrt(2)
11{x}^3{y}^2sqrt(2)
2007-12-11 13:05:20 · answer #6 · answered by Siva 5 · 0⤊ 0⤋
11 * sqrt(2) * x^3y^2
2007-12-11 13:03:32 · answer #7 · answered by harsha_kadi 2 · 0⤊ 0⤋