what is the sum of this infinite geometric sequence
24,-12,6,-3.............
I dont even know how to start this. help please
2007-12-11 04:13:00 · 3 answers · asked by nancy 1 in Science & Mathematics ➔ Mathematics
First term a = 24,
You can look (knowing it's geometric) and see that the common ratio r = -1/2
The formula for the sum of an infinite geometric sequence with | r | < 1 is:
S = a / (1-r)
So the sum is 24 / (1- (-1/2)) = 24/(3/2) = 16
2007-12-11 04:23:03 · answer #1 · answered by j s 2 · 0⤊ 0⤋
to locate the sum of a finite sequence, in basic terms upload them up. 3+6+12+24 = ? to locate the sum of a limiteless sequence it would converge. If the ratio is better than a million that is going to in no way converge so there is not any sum. a million) 6/2 = 3 18/6 = 3 etc. considering the fact that 3>a million it does not converge so there is not any countless sum That leaves you to be albe to make certain #3 on your own. solid success!
2016-12-17 14:35:34 · answer #2 · answered by ? 4 · 0⤊ 0⤋
r=-1/2so the sum is 24(1/(1+1/2) = 48/3
2007-12-11 04:22:24 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋