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A system of monatomic ideal gas starts at a pressure of 1.0E5 Pa, a volume of 5.0E-3m and an initial temperature of 300K. Gas is confined to cylinder by a movable piston. Gas slowly expands at constant volume to pressure of 3.0E5Pa. This is point B. Next it undergoes an isothermal compression to point C. At point C the pressure is 1.0E5Pa. Finally gas is compressed isobarically until it returns to its original conditions of temperature, pressure and volume.
a) Draw the PV diagram
b) find the # of moles of gas
c) Find the Temperature at B
d) Find the change in internal energy (U), Q & W (work) for isobaric process
e) find the change in U, Q &W for isochoric process
f) find net change in internal energy for entire cycle
g) Is work done on or by the gas? Explain

2007-12-11 03:40:16 · 2 answers · asked by rachhar123 1 in Science & Mathematics Physics

2 answers

g) yes

2007-12-15 10:54:57 · answer #1 · answered by Dr. R 7 · 0 0

interior the 1st case delta T = 5 To at consistent volume interior the 2nd case delta T = 4 To at consistent tension. For a monatomic gasoline Cv = 3/2R and Cp = 5/2R so deltaQ = nCvdeltaT + nCpdeltaT = 3/2R(5To) + 5/2R(quarto) = 35/2 R (273) R = 8.31 i think of to get your answer in Joules.

2016-11-02 21:45:12 · answer #2 · answered by weatherby 4 · 0 0

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