This is the graph of a straight line.
To draw a straight line, two points are required.
(7,0) and (0,- 4) would be two such points.
Draw the line thro` these points.
2007-12-12 05:37:47
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answer #1
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answered by Como 7
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First bring the -4x to the right side. 7y = -28 + 4x
Second, divide the equation by 7. y = 4/7x - 4.
This means the slope is 4/7. There is a point on the graph at (0, -4). The next point is (7,0) and there's another point at (-7, -8).
2007-12-11 03:06:59
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answer #2
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answered by 8 mile 5
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-4x + 7y = -28
=>x/7 + y/(-4) = 1
it is the equation of strainght line in interscept form
it will be a straight line intersecting x axis at x=7...and intersect y axis at y= - 4..join the two line and u will get the required graph
2007-12-11 03:09:08
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answer #3
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answered by ashish s 1
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this is an increasing function linear graph with slope 4/7 and x intercept 4 ,y intercept-4
answer.....c
2007-12-11 03:05:44
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answer #4
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answered by someone else 7
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First dot (0 , -4)
Second (7 , 0)
2007-12-11 03:06:47
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answer #5
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answered by Caladbolg 2
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-4x+7y=-28
7y=-28+4x
y=(-28+4x)/7
Then you should draw the table for this 'y=(-28+4x)/7'
2007-12-11 03:07:44
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answer #6
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answered by B S 1
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Its definitely C
2007-12-11 03:06:52
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answer #7
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answered by Anonymous
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just a guess, c?
2007-12-11 03:05:58
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answer #8
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answered by . 4
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