2007-12-10 21:28:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
r² = 0² + 10²
r² = 100
(x - 2)² + (y + 3)² = 100
x² - 4x + 4 + y² + 6y + 9 = 100
x² + y² - 4x + 6y - 87 = 0
2007-12-10 21:44:15 · answer #1 · answered by Como 7 · 2⤊ 1⤋
Distance between the centre and a point on the circle is the radius.
Thus, radius, r = (2 - 2)^2 + (-3 - 7)^2 = 100
Hence, standard fom is (x - 2)^2 + (y + 3)^2 = 100
and the general form is x^2 + y^2 - 4x + 6y - 87 = 0
2007-12-11 05:39:52 · answer #2 · answered by Madhukar 7 · 0⤊ 1⤋
standard form is
(x -- 2)^2 + (y + 3)^2 = 10^2
general form is
x^2 + y^2 -- 4x + 6y -- 87 = 0
2007-12-11 05:39:58 · answer #3 · answered by sv 7 · 0⤊ 1⤋
we can immediately write
r^2=(x-2)^2+(y+3)^2
substitute (2,7)
r^2=100
therefore the equ is
(x-2)^2+(y+3)^2=100
2007-12-11 05:39:12 · answer #4 · answered by someone else 7 · 0⤊ 0⤋
(x-2)^2+(y+3)^2=100
2007-12-11 05:37:36 · answer #5 · answered by Caps Lock (TRS_BC) 6 · 0⤊ 1⤋