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If the natural length of helical spring is 10 inches and if it takes a force of 3 pounds to keep it extended 2 inches, find the work done in streching the spring from its natural length of 15 inches

2007-12-10 17:27:49 · 1 answers · asked by msmall13 1 in Science & Mathematics Mathematics

1 answers

k = 1.5 lb/in
W = (1/2)kx^2 = (1/2)(1.5)(5)^2
W = 18.75 in•lb

2007-12-10 17:48:44 · answer #1 · answered by Helmut 7 · 0 0

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