Find the coordinates of the vertex of the following parabola:?

Question

y= -x to the secfond poer + 4x + 2

A. (2,6)
B. (-2, -6)
C. (-2, 6)
D. (2, -6)

Answer 1

Vertex:

x = -b/2a

x = -4/-2

x = 2

so the answer is A

Answer 2

The coordinates of the vertex of a parabola is (-b/2a , f(-b/2a).
It's a neat trick to use:

-b/2a = -4/2*-1 = -4/-2 = 2
f(2) = -2^2 + 4*2 + 2 = -4 + 8 + 2 = -4 + 10 = 6

ANSWER: A - (2, 6)

Hope that helps!

Answer 3

try completing the square!

y= -x^2 + 4x + 2, move number, note signs
y -2 = -x^2 + 4x, write as
y -2 = -(x^2 - 4x), note signs. Complete square by taking coefficient of the x, and squaring it, or
y -2 - 4= -(x^2 - 4x + 4), note you add same thing to both sides
y -6 = -(x-2)^2, now you have a complete square.

Vertex is (2,6). A.

Answer 4

y = -x^2 + 4x + 2

to find the x-value of the vertex:
use -b/(2a)

where b = 4 and a = -1

x = -(4)/(2*-1) = -4/-2 = 2

to find the y-value of the vertex, plug the x-value of the vertex back in the equation
y = -(2)^2 + 4(2) + 2
y = -4 + 8 + 2
y = 4 + 2
y = 6

so, the vertex is (2,6)

hope it helps
Rec

Answer 5

just do -b/2a = x
so
-4/-2 = 2 = x
plug in 2 for x
you get 6 so answer is A

Answer 6

The answer is A.

Complete the square to find the vertex.

y = -x² + 4x + 2
y - 2 = -(x² - 4x)
y - 2 - 4 = -(x² - 4x + 4)
y - 6 = -(x - 2)²

The vertex is (2, 6).

Answer 7

y = - x² + 4x + 2
y = - (x² - 4x - 2)
y = - (x² - 4x + 4 - 4 - 2)
y = - (x ² - 4x + 4) + 6
y = - (x - 2)² + 6
Vertex (2 , 6)
OPTION A

Answer 8

you cannot answer this simple question ha