-13 + 3e^x = 11
or 3e^x = 11 = 13 = 24
or e^x = 24/3 = 8
e^x = 8
means x = log8
2007-12-10 16:01:57
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answer #1
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answered by Indian Primrose 6
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-13 + 3e^x = 11
Add 13 to both sides:
3e^x = 24
Divide both sides by 3
e^x = 24/3 = 8
Take the natural logarithm of both sides (use the "ln" key on your calculator):
ln(e^x) = ln(8)
and you have
x = 2.0794
2007-12-11 00:02:19
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answer #2
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answered by rb42redsuns 6
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lol you sure it's an algrebra question. I'm in pre-cal and I'm stuck. Is E just an variable?
lemme try
-13+3e^x=11
+13 +13
3e^x=24
/3 /3
e^x=8
what is e^x?
2007-12-11 00:00:15
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answer #3
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answered by emptyspacesppk 2
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add +13 to 11 leaving you with
3e^x=24 then divide 24 by 3 leaving you with
e^x=8 then take the natural log of 8...(ln on your calulator)
x=2.07944
2007-12-11 00:04:55
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answer #4
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answered by jackie.330 2
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add 13 to both sides
3e^x = 24
divide by 3 both sides
e^x = 8
take natural log of both sides
ln e^x = ln 8 by the way ln e^x = x
x = ln 8
2007-12-11 00:02:19
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answer #5
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answered by Abe 2
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3 e^x = 24
e^x = 8
x ln e = ln 8
x = ln 8
2007-12-11 00:01:16
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answer #6
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answered by jamesyoy02 6
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3e^x = 24
e^x = 8
ln e^x = ln 8
x ln e = ln 8
x = ln 8
2007-12-12 14:15:41
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answer #7
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answered by Como 7
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...
2007-12-11 00:00:04
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answer #8
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answered by Anonymous
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