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you can mow a lawn in 3 hours. your friend can mow the same lawn in 4 hours. if the two of you work together, how long will it take to mow the lawn?

2007-12-10 15:39:45 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Work (mowed lawns) = time x rate. Your rate is 1 lawn/3 hrs; your friend's rate is 1 lawn/4 hrs.

1 mowed lawn = (Time, hrs) x (1 lawn/3 hrs + 1 lawn/4 hrs)

Time, hrs = 1/(1/3 + 1/4) = 1.71 hrs.

2007-12-10 15:47:09 · answer #1 · answered by rb42redsuns 6 · 0 0

It's a rate problem (kind of like rt=d). "You" mows at a rate of 1/3 lawns per hour; "friend" mows at a rate of 1/4 lawns per hour. Together mowing at a rate of
1/4 + 1/3 = 3/12 + 4/12 = 7/12 lawns per hour.

So it takes 12/7 hours to mow a lawn; that is, 720/7 minutes
( equals approx 1 hr 43 min.)

2007-12-10 23:52:37 · answer #2 · answered by J O 2 · 0 0

I am no nerd or anything but I believe the answer should be seven the 3 hours you can mow the lawn + the four hours your friend can mow the lawn= seven.

2007-12-10 23:55:06 · answer #3 · answered by kembe 1 · 0 0

I do 1/3 of the job in 1 hr, x/3 in x hr. Similarly, friend does x/4 of the job, and together we do 1 whole job.

x/3 + x/4 = 1
7x = 12
x = 12/7 = 1 5/7 hr.

2007-12-10 23:44:15 · answer #4 · answered by Philo 7 · 0 0

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