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How do you find out where the asymptote goes?

Example: y = 2x+3 / x+2

2007-12-10 15:36:24 · 3 answers · asked by myname_isalbert 1 in Science & Mathematics Mathematics

3 answers

I think the most straightforward way would be to take a limit as x goes to infinity. In this case, using L'hopital's Rule

lim(x->infty) 2x+3/x+2 = lim(x->infty) 2/1 = 2

If you don't know calculus, the three rules generally are:

If the degree of the numerator is less than the degree of the denominator, the asymptote is y=0

If the degree of the numerator is equal to the degree of the denominator, the asymptote is y=k, where k is the division of the leading coefficients (the leading coefficient is the coefficient in front of the term with highest power in both numerator and denominator; in this case, it is 2/1 = 2).

If the degree of the numerator is greater, there is no horizontal asymptote, and the value of the function goes to infinity.

2007-12-10 15:41:49 · answer #1 · answered by Anonymous · 0 0

x = -2 is a vertical asymptote, y = 2 is the horizontal. graph approaches y = 2 from above for x < -2, from below for x > -2.

2007-12-10 23:41:50 · answer #2 · answered by Philo 7 · 0 0

oh my god i totally just learned this in math today, so the vertical asymptote would be x=-2, and then there's something else with the horizontal asymptote but that really confuses me.

2007-12-10 23:43:28 · answer #3 · answered by strawberryfields4ever 2 · 0 1

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