your addition is fine
don't forget that i^2 = -1, so you can simplify the multiplication further:
8 - 14i - 15i^2
= 8 - 14i - 15 * (-1)
= 8 - 14i + 15
= 23 - 14i
hope this helps
2007-12-10 15:21:54
·
answer #1
·
answered by Chris W 4
·
0⤊
0⤋
The first one is correct.
Is i an ordinary unknown, or is i = â(-1)?
(4+3i)(2-5i) = 8 - 20i + 6i - 15i²
= -15i² -14i + 8
If i is a regular unknown, then using quadratic formula,
i = (14±26)/(-30)
i₊ = -4/3
i₋ = 0.4
If i = â(-1) then
-15i² -14i + 8 = -15(-1) - 14i + 8
= 15 - 14i + 8
= 23 - 14i
2007-12-10 23:36:51
·
answer #2
·
answered by DWRead 7
·
0⤊
0⤋
the addition was right, but you need to finish the multiplication:
8 - 14i - 15i² =
8 - 14i - 15(-1) =
8 - 14i + 15 =
23 - 14i
2007-12-10 23:25:02
·
answer #3
·
answered by Philo 7
·
0⤊
0⤋
i^2= -1 so
8-14i+15= 23 -14i
2007-12-10 23:22:35
·
answer #4
·
answered by Misanthropist 3
·
0⤊
0⤋
Well, the first one is correct. But the second one, it's 23-14i
2007-12-10 23:42:19
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
I agree with your first answer.
Your second answer looks fine as far as it goes. Now just make use of the fact that i^2 = -1 to simplify it even further. (I'm assuming i means the imaginary unit in this context.)
It doesn't look like you suck at math to me...
2007-12-10 23:23:46
·
answer #6
·
answered by Steve H 5
·
1⤊
0⤋
the first one is right... for the second one you have to remember that i^2 is equal to -1. therefore you should be able to simplify it further.
2007-12-10 23:22:59
·
answer #7
·
answered by Kar Kar 1
·
0⤊
0⤋
First is right..and second is right too..Congrats!
2007-12-10 23:21:51
·
answer #8
·
answered by mrr86 5
·
0⤊
1⤋
school is for foools!
haha just playin just playin
stay in school!
2007-12-10 23:28:07
·
answer #9
·
answered by D 2
·
0⤊
1⤋
both are right
2007-12-10 23:25:09
·
answer #10
·
answered by Anonymous
·
0⤊
1⤋