√-25 + √-16 = ?
the square root of -25 plus the square root of -16
2007-12-10 14:04:20 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
but you can't square root a negative
2007-12-10 14:07:54 · update #1
5i + 4i
9i
2007-12-10 14:07:17 · answer #1 · answered by Jonathan S 2 · 0⤊ 0⤋
Well the square root of negative 1 is i.
so the square root of -25 is 5i
and the square root of -16 is 4i
5i+4i and you get 9i as your answer. the i stands for imaginary numbers.
2007-12-11 19:26:32 · answer #2 · answered by Rocketman 6 · 0⤊ 0⤋
This is a complex numbers problem
the square root of -25 is 5i, where i is an imaginary number
the square root of -16 is 4i
there for:
5i+4i = 9i
2007-12-10 22:11:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
â-25 + â-16 = ?
Let i = â-1, the imaginary number
then
â-25 + â-16
= â25 i + â16 i
= 5 i + 4 i
= 9 i
or - 9 i
2007-12-10 22:11:10 · answer #4 · answered by vlee1225 6 · 0⤊ 0⤋
square root(-25) plus square root(-16) = 9 i
2007-12-10 22:12:13 · answer #5 · answered by Kay 2 · 0⤊ 0⤋
v-25 + v-16 = (-5) + (-4)
= -9
2007-12-10 22:16:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
9
2007-12-10 22:08:23 · answer #7 · answered by >_> 4 · 0⤊ 1⤋
The 9i people are correct.
â-25 + â-16 = 5i + 4i = 9i
2007-12-10 22:12:43 · answer #8 · answered by Edgard L 2 · 0⤊ 0⤋
â-25 + â-16 = 5i + 4i = 9i
2007-12-10 22:07:20 · answer #9 · answered by Philo 7 · 0⤊ 0⤋
-9
2007-12-10 22:07:13 · answer #10 · answered by John 4 · 0⤊ 2⤋