I've had about 8 g-friends total and I'm single now. Should I look for the right one or should I keep practicing?
2007-12-10 12:35:58 · 7 answers · asked by remove me 5 in Entertainment & Music ➔ Polls & Surveys
You'll know when it happens my dear friend...trust me!
2007-12-11 13:10:38 · answer #1 · answered by Mustang Sally 5 · 1⤊ 1⤋
Take it easy ... wait ... be patient ... and eventually ... maybe ... someday there WILL be the "Right" one showing up ...
(I am always hoping ... and that is for sure)
DO NOT SETTLE for LESS than the best -- and don't be USED. (This is from the SURVIVOR of a Short Disaster of a Marriage to an Abusive, Violent Sociopath -- who for the past 2 decades has had to live with that ex's torments AFTER the divorce).
I've waited more than 2 decades to start dating once again ... and guess what ... I was SURPRISED this year by meeting someone Kind, Gentle, Caring and Loving .. Someone who is more than willing to be RESPECTFUL of me, Cherish Me, and yes, I do so much enjoy our Intelligent (Witty) Banter and communication -- which is MOST important in any relationship.
For Physical Attraction is transitory -- but REAL Beauty -- that is at the CORE of the Person you choose.
LOOK for the BEAUTY Within .. and ... if we are VERY lucky ... then we WILL find that one true love who will cherish us for the rest of our lives.
2007-12-10 20:44:15 · answer #2 · answered by sglmom 7 · 1⤊ 0⤋
I must not have been very good at it. I had to practice A LOT before finding the right one. I had fun though!!!
2007-12-10 20:40:35 · answer #3 · answered by wildwillow 3 · 1⤊ 0⤋
311
2007-12-10 20:39:11 · answer #4 · answered by Kenny E 7 · 0⤊ 1⤋
Eleven and half.
C'mon man, everyone is different. Stop haveing practice girlfriends when you get a great one.
2007-12-10 20:39:53 · answer #5 · answered by Mark M 5 · 2⤊ 1⤋
so you have 8 sisters? jk!
2007-12-10 20:40:45 · answer #6 · answered by Anonymous · 1⤊ 0⤋
It depends on the person... don't look.. they will find you xD
2007-12-10 20:39:46 · answer #7 · answered by Kimberlee 5 · 1⤊ 0⤋