2007-12-10 12:34:43 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^2 + 10x + x + 5
2x^2 + 11x + 5
2007-12-10 12:37:29 · answer #1 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
This problem is distribution. To do this, you use a method called FOIL. This stands for "First Outer Inner Last"
What you do is multiply the first part of the first parentheses by the first and second part of the second parentheses. Then you multiply the second part of the first parentheses by the first and second part of the second parentheses.
Let me show you.
(2x+1)(x+5) Multiply 2x and x, then 2x and 5 to get 2x^2+10x
Then multiply 1 and x, then 1 and 5 to get x+5.
Add the two together 2x^2+10x+x+5
2x^2+11x+5
There you go! That's your answer. Simple as that!
2007-12-10 12:41:53 · answer #2 · answered by shortie_212003 2 · 0⤊ 0⤋
Break it up in parts
(2x+1)(x+5)
= 2x (x + 5) + 1 (x + 5)
= 2x^2 + 10x + x + 5
= 2x^2 + 11x + 5
2007-12-10 12:38:55 · answer #3 · answered by vlee1225 6 · 0⤊ 0⤋
(2x+1)(x+5)
Multiply -> 2x²+10x+x+5
Add together the like terms -> 2x²+11x+5
2007-12-10 12:39:08 · answer #4 · answered by My Karma Ran over Your Dogma 2 · 0⤊ 0⤋
(2x+1)(x+5)
= 2x^2+10x+x+5
= 2x^2+11x+5
2007-12-10 12:39:17 · answer #5 · answered by tieu linh tinh 1 · 0⤊ 0⤋
FOIL
(2x*x)+(2x*5)+(1*x)+1*5)
2x^2 + 10x + 1x + 5
2x^2 + 11x + 5
2007-12-10 12:40:39 · answer #6 · answered by Tink M 1 · 0⤊ 0⤋
First, outer, inner, last terms:
First 2x^2
Outer 10x
Inner x
Last 5
Add them together to get 2x^2 +11x +5
2007-12-10 12:38:12 · answer #7 · answered by Petri 3 · 0⤊ 0⤋
2x^2+11x+5
2007-12-10 12:37:56 · answer #8 · answered by IE 3 · 0⤊ 0⤋
foil (2x+1)(x+5)
2xsquared
10x
x
5
=
2xsquared +10x+x+5
2x squared +11x+5
2007-12-10 12:45:16 · answer #9 · answered by aeebonystar 1 · 0⤊ 0⤋
FOIL-Front, inner, outer, last.
2x^2 + x + 10x +5 = 0
2x^2 + 11x + 5 = 0
2007-12-10 12:38:29 · answer #10 · answered by Anonymous · 0⤊ 0⤋