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During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapults that are made with surgical hose mounted on a window frame. A balloon filled with dyed water is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the stretching of the hose obeys Hooke's law with a spring constant of 112 N/m. If the hose is stretched by 4.50 m and then released, how much work does the force from the hose do on the balloon in the pouch by the time the hose reaches its relaxed length?

2007-12-10 12:29:41 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

the work will be equal to the energy stored at full elongation
.5*112*4.5^2
1134 J

j

2007-12-11 02:39:20 · answer #1 · answered by odu83 7 · 0 0

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