x/x+2 + 4/x-2
2007-12-10 11:47:19 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x/(x+2) + 4/(x-2)
= (x(x-2) + 4(x+2))/(x^2 - 4)
= (x^2 + 2x + 8)/(x^2 - 4)
2007-12-10 11:51:55 · answer #1 · answered by Blake 3 · 0⤊ 0⤋
I assume you meant
x / ( x+2 ) + 4 / ( x-2 )
Give each term a common denominator...
x ( x - 2 ) / ( x + 2 ) ( x - 2 ) + 4 ( x + 2 ) / ( x + 2 ) ( x - 2 )
add...
( x ( x - 2 ) + 4 ( x + 2 ) ) / ( x + 2 ) ( x - 2 )
simplify...
( x² - 2x + 4x + 8 ) / ( x + 2 ) ( x - 2 )
( x² + 6x + 8 ) / ( x + 2 ) ( x - 2 )
factor the numerator...
( x + 4 ) ( x + 2 ) / ( x + 2 ) ( x - 2 )
cancel common terms...
( x + 4 ) / ( x - 2 )
2007-12-10 11:51:59 · answer #2 · answered by jgoulden 7 · 0⤊ 1⤋
You need some perithesese.
Do you mean:
x/(x+2) + 4/(x-2)?
Which would be
(x(x-2))/(x^2-4)+(4(x+2))/(x^2-4)
Simplifies :
(x^2-2x+4x+8)/(x^2-4)
(x^2+2x+8)/(x^2-4)
However if you mean...
(x/x)+2+(4/x)-2
This simplifies to
(x+4)/x or possibly
1+4/x
Edit: jgoulden
-2x+4x=2x not 6x
2007-12-10 11:56:54 · answer #3 · answered by zenock 4 · 0⤊ 0⤋
[x(x - 2) + 4(x + 2)] / x^2 - 4
(x^2 - 2x +4x + 8) / x^2 - 4
(x^2 - 2x + 8) / x^2 - 4
[(x - 4) (x + 2)] / (x - 2) (x + 2)
x - 4 / x - 2
2007-12-10 12:54:12 · answer #4 · answered by criselda 3 · 0⤊ 0⤋
x / x + 2 + 4 / x - 2
add
(x + 4) / 2x
take x out of numerator and denominator
4 / x
2007-12-10 12:11:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x/(x+2) + 4/(x-2)= [x(x-2) +4(x+2)]/[(x-2)(x+2)]= (x^2 + 2x +8)/[(x-2)(x+2)]
2007-12-10 11:55:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x/x+2 + 4/x-2
You probably mean
x/(x + 2) + 4/(x - 2)
The LCD is (x + 2)(x - 2)
x(x - 2)/[(x + 2)(x - 2)] + 4(x + 2)/[(x + 2)(x - 2)]
(x^2 - 2x + 4x + 8)/[(x + 2)(x - 2)]
(x^2 + 2x + 8)/[(x + 2)(x - 2)]
2007-12-10 11:55:44 · answer #7 · answered by kindricko 7 · 0⤊ 0⤋