IN SOCCER, DANIEL SCORED 6 GOALS IN HIS LAST 10 ATTEMPT.
WHAT IS THE PROBABILITY OF DANIEL SCORING A GOAL ON HIS NEXT ATTEMPT?
SUPPOSE DANIEL ATTEMPTS TO SCORE 50 GOALS. HOW MANY GOALS WILL HE MAKE?
2007-12-10 11:00:31 · 7 answers · asked by leah 1 in Science & Mathematics ➔ Mathematics
there is a formula to use for this problem and i am having hard time trying to figure out the first part of the problem which is what is the probability of daniel scoring a goal on his next attempt. can once one help me witht the formula that needs to be used. thanks to those who have provided the information dust far.
2007-12-10 11:15:06 · update #1
Let X be the number of goals Daniel scores. X is a random variable and has the binomial distribution with n = 50 trials and estimated success probability p = 0.6.
In general, if X has the binomial distribution with n trials and a success probability of p then
P[X = x] = n!/(x!(n-x)!) * p^x * (1-p)^(n-x)
for values of x = 0, 1, 2, ..., n
P[X = x] = 0 for any other value of x.
this is found by looking at the number of combination of x objects chosen from n objects and then a total of x success and n - x failures.
Or, to be more accurate, the binomial is the sum of n independent and identically distributed Bernoulli trials.
A Bernoulli trial is an event where there are only two outcomes, a success and a failure. The probability of a success is given by p. A coin flip is a good example of a Bernoulli trial.
the mean of the binomial distribution is n * p
the variance of the binomial distribution is n * p * (1 - p)
the standard deviation is the square root of the variance.
The mean, or expectation, of the binomial is n * p = 50 * 6/10 = 30.
2007-12-11 15:45:14 · answer #1 · answered by Merlyn 7 · 0⤊ 0⤋
The probability is 6/10, 60% or 0.60 (They all mean the same thing). So we expect 6 out of every 10 attempts will be successful.
For the second part of the question we expect that Daniel will make 60% of his 50 attempts. ==> .60 x 50 = 30.
2007-12-10 11:09:01 · answer #2 · answered by betamaxreturns 3 · 0⤊ 0⤋
Daniel's probabilty of scoring the next goal is 60%.
60% of 50= .60x50=30
Daniel will score 30 goals.
2007-12-10 11:06:27 · answer #3 · answered by doctorwhofan101 1 · 0⤊ 0⤋
if he attemps at 50 goals you start out with 6 out of 10 so 6 times 5 =30 so i think the answer would be 30
2007-12-10 11:07:16 · answer #4 · answered by soccergal 1 · 0⤊ 0⤋
he is hitting 60%
his chances on the next goal are .60
and if he attempts 50 goals he is likely to get 30
2007-12-10 11:04:10 · answer #5 · answered by ignoramus 7 · 0⤊ 0⤋
probability is better than 50%, 30 goals.
2007-12-10 11:04:57 · answer #6 · answered by Gardog 3 · 0⤊ 0⤋
first part is either .6 probability or 60% probability
second part is .6 times 50 which is 30 i think i did it in my head
2007-12-10 11:04:47 · answer #7 · answered by Anonymous · 0⤊ 0⤋