Math Help!?

Question

An amoeba reprduces by doubling every 20 minutes. If an amoeba is placed in a specimen dish at 12:00 noon, how many amoebas will be in the dish at 5:00 P.M.?

Please show the work or steps you did to solve the problem

Answer 1

ok - there are 5 hours in between 12 and 5.... so how many 20 minutes are in 5 hours? well - there are 3 x 20 minutes in each hour... and if we times 3 by 5 (the amount of twenty minutes in one hour times the amount of hours) we get 15. hope this helps.

Answer 2

1. What is the elapsed time (how many hours are going to pass).

5 Hours, now, there are 60 minutes in 1 hour so, 60 times 5 is 300 minutes. If 300 minutes are going to pass then you must think how many increments of 20 minutes will happen within those 300 minutes, or, you can think of it in terms of 300 divided by 20 which is equal to 15, so, the amoeba doubles 15 times.

On to part 2. Now, you could do 1 x'2, x'2, x'2, x'2 .... you could do that 15 times, or that can be expressed as or u could just do 2 times 15 = 30. So I'd say 30 amoeba's for the final answer.

Make sure to plug it back in to see if it works.

Answer 3

Amoeba doubles every 20 minutes. The amoeba has 5 hours.

5 * 60 = 300 minutes

300/20 = 30/2 = 15

The amoeba will double 15 times.

now you double each number twice, since each amoeba doubles.(15 times)

1 amoeba

2
4
8
16
32 (5)
64 (6)
128
256
512

etc......

hope i helped

Answer 4

Well think about how many times the Amoeba will double. If it does it every twenty minutes, and it sits in the dish for five hours, it will reproduce three times every hour for five hours. So it will reproduce fifteen times.

1, 2, 4, 8, 16...

I believe you could also go 2^15....

Answer 5

12 to 5 is 5 hours
there are 15 20 minute periods in 5 hours
so they will be 2^15 in that time
2^ 5 is 32
so multiply 32 x 32 x32 =32 768 amoebae

Answer 6

such an easy problem, can't believe you can't solve it.

Answer 7

Its not too hard, you can do it.