Ok so basically, there is a diagonal arrow indicating a downward push on a 75kg box. This arrow represents 50N and forms a 30 degree angle with the box (under the arrow). How do i find Fn and the horizontal + vertical ocmponents given this information. Please help!
BY THE WAY: FRICTION IS NEGLIGIBLE IN THIS PROBLEM!
2007-12-10 10:20:07 · 1 answers · asked by kerwin 1 in Science & Mathematics ➔ Physics
You may consider a right triangle with this force as the hypotenuse. How to pick the two legs would depend on the situation. If the box is on a horizontal surface, the potential movement would be horizontal and the normal force would be vertical. Here, I do not quite understand what you mean about "30 degree angle with the box ". Is 30 degree angle with the horizontal surface or the vertical surface of the box?
Assume the force form a 30 degree angle with the horizontal. In the triangle formed by the force, the horizontal and vertical lines, the vertical force component is F*sin 30° = F/2 = 25N, and the horizontal force component is F*cos 30° = F*sqrt(3)/2 = 43N.
Notice that Fn from the box to the floor is now increased because of the 50N force on the box:
Fn = (75*9.8 + 25)N
2007-12-11 14:04:14 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋