CHEM help please!!!?

Question

Radon-222 decays to a stable nucleus by a series of three alpha emission and two beta emission. what is the product?
A positron collides with an electron. what is the product of this collision?

can someone please help me out? thanks

Answer 1

Radon has an atomic number of 86 and this isotope has a mass number of 222. The 3 alpha particle emissions will decrease the mass number by 12 to 210 and will decrease the atomic number by 6 to 80. The two beta emissions will raise the atomic by 2 to 82. So, your final product is Lead-210.

(I hope that one's right.)

When a positron and an electron collide, they form a neutron.