2007-12-10 09:51:06 · 4 answers · asked by Dee 1 in Science & Mathematics ➔ Mathematics
Let X be the wins
Let Y be the losses
The soccer team won 3 times as many games as they lost:
so X = 3Y
They played 28 games:
so X + Y = 28
then do a little algebra and solve for Y:
X + Y = 28
Y = 28 - X
then replace Y in our first equation with our solution for it we just found:
X = 3Y
X = 3(28 - X)
Now solve for X:
X = 84 - 3X
X + 3X = 84
4X = 84
X = 21
Finally, we can use the x we found to solve for Y with our original equation:
X = 3Y
21 = 3Y
7 = Y
Y = 7
Hence there were 21 Wins and 7 Losses.
2007-12-10 10:06:10 · answer #1 · answered by Bill 2 · 0⤊ 0⤋
28/4=7 =7 They played four games because they won 3 and lost 1 which leads you to the process of division... therefore 28 = 4 the number of games played=7 7 is the answer
2007-12-10 18:00:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x=games lost
3x = games won
3x + x = 28
4x = 28
x=7
They lost 7 games.
2007-12-10 17:55:28 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋
they lost seven games
2007-12-10 17:59:16 · answer #4 · answered by MYA a.k.a BEBA 2 · 0⤊ 0⤋