x = [ - 6 ±√(36 + 60) ] / 6
x = [ - 6 ±√(96) ] / 6
x = [ - 6 ± 4√(6) ] / 6
2007-12-10 09:25:32
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answer #1
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answered by Como 7
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if you've got the right software (Maple), just type:
solve(3*x^2+6*x-5=0,x);
then press enter and view the results immediately:
-1+(2/3)*sqrt(6), -1-(2/3)*sqrt(6)
you could use the quadratic equation, or use the method of completing the square (which is how the quadratic equation is derived, so I guess "complete the square" is the best answer for HOW to solve -- consult any elementary algebra book for more details, or google).
2007-12-10 17:19:24
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answer #2
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answered by Anonymous
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3x^2+6x-5 = 0
Use quadratic formula,
x = [-6 ± â(6^2+60)]/6 = -1 ± 2â6 / 3
2007-12-10 17:17:27
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answer #3
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answered by sahsjing 7
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3x^2+6x-5 =
x = -1 ± â66 / 6
2007-12-10 17:21:58
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answer #4
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answered by Jared K. 2
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I think it would be...
3xsquared + 6x- 0
9x + 6x - 5 = 0
15x - 5 = 0
+5 +5
15x = 5
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15 15
x = 1/3
But I suck at math so I dunno. That's how we were taught.
2007-12-10 17:19:42
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answer #5
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answered by Schrei 3
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use the quadratic equation
2007-12-10 17:16:46
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answer #6
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answered by David L 2
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